'Mile and Time Downwind Distance\r'

'1. A trim travels from Orlando to Denver and back again. On the five-hour spark off from Orlando to Denver, the shroud has a tailwind of 40 miles per hour. On the bring back trip from Denver to Orlando, the plane faces a headwind of 40 miles per hour. This trip analyses sise hours. What is the drive on of the airplane in still air? X = speed of plane in still air (x+40) = speed of plane downwind (x-40) =speed of plane against the wind maintain = speed *travel time downwind outer space = headwind distance 5(x+40) = 6(x-40) 5x+200=6x-240 6x-5x=240+200 x=440 miles per hourSo, The speed of the plane in still air is 440 mph if I am not mistaken. 2. Two bicycles throw in from Miami Beach going in opposite directions. The frontmost bicycle is traveling at 10 miles per hour. The bite bicycle travels at 5 miles per hour. How long does it take until the bikes atomic number 18 45 miles apart? D=RT 45=(10+5)T 45=15T T=445/15 T=3 hours. 3. Jesse rents a moving van for $75 and must (prenominal) pay $2 per mile. The following week, Alex rents the same van, is aerated $80 for the rental and $1. 50 per mile. If they each paid the same criterion and drove the same act of miles, how far did they each travel? 5+2m=80+1. 5m subtract 75 from twain sides subtract 1. 5m from both sides .5m=5 multiply both sides by 2 m=10 miles . 4. During a 4th of July weekend, 32 vehicles became trapped on the Sunshine Skyway dyad while it was being repaved. A recent metropolis ordinance decreed that only cars with 4 wheels and trucks with six wheels could be on the bridge at some(prenominal) given time. If there were 148 tires that needed to be replaced to referable to damage, how many cars and trucks were involved in the incident? Okay. there were 32 cars , we have x + y = 32 ars have 4 wheels so 4x , trucks have 6 wheels so 6x the total number of wheels adds up to 148, so 4x +6y = 14: x+y=32 4x + 6y = 148 -4x †4y = -128 4x + 6y = 148. 5. For this question, you leave be hind need a parent/guardian or a friend. Have this individual grab a handful of coins making sure there are only two types of coins in the group (i. e. , nickels and dimes, quarter and pennies, pennies and dimes, etc). Your parent/guardian or friend should announce you the type of coins they’ve chosen, how many coins they have and the dollar amount of the group.From this information, you will set up two sets of equations and set how many of each coin they have in their hand. Please send your instructor the name of the individual who helped you with this question, your two equations and the work you did to solve the system. She has 11 coins charge 83 cents. P and Q will the number of pennies and quarters, P + Q = 11 P + 25Q = 83 P + 25Q †P + Q = 24 Q = 83 †11 = 72. So, 24 Q = 72 Q = 3. Q = 3 can be put into the equation to solve for P. If we use the first equation, we get P + 3 = 11 P = 8, so 3 quarters and eight pennies.\r\n'